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20146170015353 is a prime number
BaseRepresentation
bin1001001010010101001010…
…10011101010111001111001
32122022221210020010122022002
410211022211103222321321
510120033324010442403
6110503004524510345
74146340605451064
oct445124523527171
978287706118262
1020146170015353
116467a40845018
1223145676ab3b5
13b31a1122aa95
144d91190b38db
1524e0ac5c5188
hex1252a54eae79

20146170015353 has 2 divisors, whose sum is σ = 20146170015354. Its totient is φ = 20146170015352.

The previous prime is 20146170015337. The next prime is 20146170015401. The reversal of 20146170015353 is 35351007164102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20145761490409 + 408524944 = 4488403^2 + 20212^2 .

It is a cyclic number.

It is not a de Polignac number, because 20146170015353 - 24 = 20146170015337 is a prime.

It is not a weakly prime, because it can be changed into another prime (20146170065353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10073085007676 + 10073085007677.

It is an arithmetic number, because the mean of its divisors is an integer number (10073085007677).

Almost surely, 220146170015353 is an apocalyptic number.

It is an amenable number.

20146170015353 is a deficient number, since it is larger than the sum of its proper divisors (1).

20146170015353 is an equidigital number, since it uses as much as digits as its factorization.

20146170015353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 38.

Adding to 20146170015353 its reverse (35351007164102), we get a palindrome (55497177179455).

The spelling of 20146170015353 in words is "twenty trillion, one hundred forty-six billion, one hundred seventy million, fifteen thousand, three hundred fifty-three".