2015113103 has 4 divisors (see below), whose sum is σ = 2022233928. Its totient is φ = 2007992280.

The previous prime is 2015113049. The next prime is 2015113117. The reversal of 2015113103 is 3013115102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3013115102 = 2 ⋅1506557551.

It is a cyclic number.

It is not a de Polignac number, because 2015113103 - 2²⁰ = 2014064527 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2015113123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3559988 + ... + 3560553.

It is an arithmetic number, because the mean of its divisors is an integer number (505558482).

Almost surely, 2^2015113103 is an apocalyptic number.

2015113103 is a deficient number, since it is larger than the sum of its proper divisors (7120825).

2015113103 is an equidigital number, since it uses as much as digits as its factorization.

2015113103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7120824.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 2015113103 is about 44890.0111717518. The cubic root of 2015113103 is about 1263.0866423465.

Adding to 2015113103 its reverse (3013115102), we get a palindrome (5028228205).

The spelling of 2015113103 in words is "two billion, fifteen million, one hundred thirteen thousand, one hundred three".