201512113 has 4 divisors (see below), whose sum is σ = 219831408. Its totient is φ = 183192820.

The previous prime is 201512111. The next prime is 201512117. The reversal of 201512113 is 311215102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201512113 - 2¹ = 201512111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201512111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9159631 + ... + 9159652.

It is an arithmetic number, because the mean of its divisors is an integer number (54957852).

Almost surely, 2^201512113 is an apocalyptic number.

It is an amenable number.

201512113 is a deficient number, since it is larger than the sum of its proper divisors (18319295).

201512113 is a wasteful number, since it uses less digits than its factorization.

201512113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18319294.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 201512113 is about 14195.4962223939. The cubic root of 201512113 is about 586.2736639521.

Adding to 201512113 its reverse (311215102), we get a palindrome (512727215).

The spelling of 201512113 in words is "two hundred one million, five hundred twelve thousand, one hundred thirteen".