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201512117 is a prime number
BaseRepresentation
bin11000000001011…
…01010010110101
3112001011212122202
430000231102311
5403041341432
631555034245
74664552612
oct1400552265
9461155582
10201512117
11a3826044
125759b985
1332996651
141ca97509
1512a57462
hexc02d4b5

201512117 has 2 divisors, whose sum is σ = 201512118. Its totient is φ = 201512116.

The previous prime is 201512111. The next prime is 201512149. The reversal of 201512117 is 711215102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 150945796 + 50566321 = 12286^2 + 7111^2 .

It is a cyclic number.

It is not a de Polignac number, because 201512117 - 218 = 201249973 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201512111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100756058 + 100756059.

It is an arithmetic number, because the mean of its divisors is an integer number (100756059).

Almost surely, 2201512117 is an apocalyptic number.

It is an amenable number.

201512117 is a deficient number, since it is larger than the sum of its proper divisors (1).

201512117 is an equidigital number, since it uses as much as digits as its factorization.

201512117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 140, while the sum is 20.

The square root of 201512117 is about 14195.4963632837. The cubic root of 201512117 is about 586.2736678312.

Adding to 201512117 its reverse (711215102), we get a palindrome (912727219).

The spelling of 201512117 in words is "two hundred one million, five hundred twelve thousand, one hundred seventeen".