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201521141 is a prime number
BaseRepresentation
bin11000000001011…
…11011111110101
3112001012100000222
430000233133311
5403042134031
631555144125
74664621123
oct1400573765
9461170028
10201521141
11a38318a8
12575a5045
133299a7a3
141ca9a913
1512a59e7b
hexc02f7f5

201521141 has 2 divisors, whose sum is σ = 201521142. Its totient is φ = 201521140.

The previous prime is 201521113. The next prime is 201521161. The reversal of 201521141 is 141125102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 201214225 + 306916 = 14185^2 + 554^2 .

It is a cyclic number.

It is not a de Polignac number, because 201521141 - 210 = 201520117 is a prime.

It is a super-2 number, since 2×2015211412 = 81221540539883762, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201521161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100760570 + 100760571.

It is an arithmetic number, because the mean of its divisors is an integer number (100760571).

Almost surely, 2201521141 is an apocalyptic number.

It is an amenable number.

201521141 is a deficient number, since it is larger than the sum of its proper divisors (1).

201521141 is an equidigital number, since it uses as much as digits as its factorization.

201521141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 201521141 is about 14195.8142070119. The cubic root of 201521141 is about 586.2824190909.

Adding to 201521141 its reverse (141125102), we get a palindrome (342646243).

The spelling of 201521141 in words is "two hundred one million, five hundred twenty-one thousand, one hundred forty-one".