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20152444051 = 172311696137
BaseRepresentation
bin10010110001001011…
…011110010010010011
31221000110101020011201
4102301023132102103
5312233011202201
613131412452031
71312252643125
oct226113362223
957013336151
1020152444051
118601590543
123aa501a017
131b9215110c
14d92649215
157ce32e801
hex4b12de493

20152444051 has 4 divisors (see below), whose sum is σ = 20164141912. Its totient is φ = 20140746192.

The previous prime is 20152444043. The next prime is 20152444057. The reversal of 20152444051 is 15044425102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20152444051 - 23 = 20152444043 is a prime.

It is a super-2 number, since 2×201524440512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20152444057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5846346 + ... + 5849791.

It is an arithmetic number, because the mean of its divisors is an integer number (5041035478).

Almost surely, 220152444051 is an apocalyptic number.

20152444051 is a deficient number, since it is larger than the sum of its proper divisors (11697861).

20152444051 is a wasteful number, since it uses less digits than its factorization.

20152444051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11697860.

The product of its (nonzero) digits is 6400, while the sum is 28.

Adding to 20152444051 its reverse (15044425102), we get a palindrome (35196869153).

The spelling of 20152444051 in words is "twenty billion, one hundred fifty-two million, four hundred forty-four thousand, fifty-one".

Divisors: 1 1723 11696137 20152444051