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20154014431321 is a prime number
BaseRepresentation
bin1001001010100011110001…
…10111101111100001011001
32122100201000220210021000211
410211101320313233201121
510120200410143300241
6110510343145531121
74150036160053351
oct445217067574131
978321026707024
1020154014431321
1164702a6806921
122315b967a3aa1
13b32691468434
144d9660c3bb61
1524e3bb0db781
hex125478def859

20154014431321 has 2 divisors, whose sum is σ = 20154014431322. Its totient is φ = 20154014431320.

The previous prime is 20154014431319. The next prime is 20154014431351. The reversal of 20154014431321 is 12313441045102.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13998335859225 + 6155678572096 = 3741435^2 + 2481064^2 .

It is a cyclic number.

It is not a de Polignac number, because 20154014431321 - 21 = 20154014431319 is a prime.

Together with 20154014431319, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (20154014431301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10077007215660 + 10077007215661.

It is an arithmetic number, because the mean of its divisors is an integer number (10077007215661).

Almost surely, 220154014431321 is an apocalyptic number.

It is an amenable number.

20154014431321 is a deficient number, since it is larger than the sum of its proper divisors (1).

20154014431321 is an equidigital number, since it uses as much as digits as its factorization.

20154014431321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 20154014431321 its reverse (12313441045102), we get a palindrome (32467455476423).

The spelling of 20154014431321 in words is "twenty trillion, one hundred fifty-four billion, fourteen million, four hundred thirty-one thousand, three hundred twenty-one".