Base | Representation |
---|---|
bin | 11101010101000000101… |
… | …010011000000011110001 |
3 | 21010200011101210020222020 |
4 | 131111000222120003301 |
5 | 231010042133342431 |
6 | 4141512341502053 |
7 | 265416045460350 |
oct | 35250052300361 |
9 | 7120141706866 |
10 | 2015424512241 |
11 | 707811660168 |
12 | 286729711929 |
13 | 118091024baa |
14 | 6d793219997 |
15 | 3765c1e8696 |
hex | 1d540a980f1 |
2015424512241 has 64 divisors (see below), whose sum is σ = 3284960624640. Its totient is φ = 1072871193600.
The previous prime is 2015424512219. The next prime is 2015424512249. The reversal of 2015424512241 is 1422154245102.
It is not a de Polignac number, because 2015424512241 - 25 = 2015424512209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2015424512249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 164666200 + ... + 164678438.
It is an arithmetic number, because the mean of its divisors is an integer number (51327509760).
Almost surely, 22015424512241 is an apocalyptic number.
2015424512241 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
2015424512241 is a deficient number, since it is larger than the sum of its proper divisors (1269536112399).
2015424512241 is a wasteful number, since it uses less digits than its factorization.
2015424512241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16934.
The product of its (nonzero) digits is 25600, while the sum is 33.
Adding to 2015424512241 its reverse (1422154245102), we get a palindrome (3437578757343).
The spelling of 2015424512241 in words is "two trillion, fifteen billion, four hundred twenty-four million, five hundred twelve thousand, two hundred forty-one".
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