Base | Representation |
---|---|
bin | 10010110001010010… |
… | …011001111111001011 |
3 | 1221000120210120011211 |
4 | 102301102121333023 |
5 | 312233442331301 |
6 | 13131515433551 |
7 | 1312304252512 |
oct | 226122317713 |
9 | 57016716154 |
10 | 20154261451 |
11 | 8602611a25 |
12 | 3aa57558b7 |
13 | 1b926393bc |
14 | d9299d679 |
15 | 7ce58d051 |
hex | 4b1499fcb |
20154261451 has 4 divisors (see below), whose sum is σ = 21030533712. Its totient is φ = 19277989192.
The previous prime is 20154261401. The next prime is 20154261467. The reversal of 20154261451 is 15416245102.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20154261451 - 29 = 20154260939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20154261401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 438136096 + ... + 438136141.
It is an arithmetic number, because the mean of its divisors is an integer number (5257633428).
Almost surely, 220154261451 is an apocalyptic number.
20154261451 is a deficient number, since it is larger than the sum of its proper divisors (876272261).
20154261451 is an equidigital number, since it uses as much as digits as its factorization.
20154261451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 876272260.
The product of its (nonzero) digits is 9600, while the sum is 31.
The spelling of 20154261451 in words is "twenty billion, one hundred fifty-four million, two hundred sixty-one thousand, four hundred fifty-one".
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