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20154324413 = 88722721899
BaseRepresentation
bin10010110001010010…
…101001010110111101
31221000120220202112202
4102301102221112331
5312234001340123
613131521041245
71312304634206
oct226122512675
957016822482
1020154324413
118602655263
123aa5786225
131b9265bc62
14d929b85ad
157ce5a1a28
hex4b14a95bd

20154324413 has 4 divisors (see below), whose sum is σ = 20177047200. Its totient is φ = 20131601628.

The previous prime is 20154324361. The next prime is 20154324419. The reversal of 20154324413 is 31442345102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20154324413 - 26 = 20154324349 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20154324419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11360063 + ... + 11361836.

It is an arithmetic number, because the mean of its divisors is an integer number (5044261800).

Almost surely, 220154324413 is an apocalyptic number.

It is an amenable number.

20154324413 is a deficient number, since it is larger than the sum of its proper divisors (22722787).

20154324413 is an equidigital number, since it uses as much as digits as its factorization.

20154324413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22722786.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 20154324413 its reverse (31442345102), we get a palindrome (51596669515).

The spelling of 20154324413 in words is "twenty billion, one hundred fifty-four million, three hundred twenty-four thousand, four hundred thirteen".

Divisors: 1 887 22721899 20154324413