201543325229 has 2 divisors, whose sum is σ = 201543325230. Its totient is φ = 201543325228.

The previous prime is 201543325213. The next prime is 201543325267. The reversal of 201543325229 is 922523345102.

It is an a-pointer prime, because the next prime (201543325267) can be obtained adding 201543325229 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123703441225 + 77839884004 = 351715^2 + 278998^2 .

It is a cyclic number.

It is not a de Polignac number, because 201543325229 - 2⁴ = 201543325213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201543325192 and 201543325201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201543325289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100771662614 + 100771662615.

It is an arithmetic number, because the mean of its divisors is an integer number (100771662615).

Almost surely, 2^201543325229 is an apocalyptic number.

It is an amenable number.

201543325229 is a deficient number, since it is larger than the sum of its proper divisors (1).

201543325229 is an equidigital number, since it uses as much as digits as its factorization.

201543325229 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 38.

The spelling of 201543325229 in words is "two hundred one billion, five hundred forty-three million, three hundred twenty-five thousand, two hundred twenty-nine".