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2015543435441 is a prime number
BaseRepresentation
bin11101010101000111110…
…000000010000010110001
321010200110200120011221012
4131111013300002002301
5231010313104413231
64141532230440305
7265422021345254
oct35250760020261
97120420504835
102015543435441
117078727a69a8
12286761503095
131180ac862953
146d7a4d3509b
1537667889e2b
hex1d547c020b1

2015543435441 has 2 divisors, whose sum is σ = 2015543435442. Its totient is φ = 2015543435440.

The previous prime is 2015543435429. The next prime is 2015543435453. The reversal of 2015543435441 is 1445343455102.

It is a balanced prime because it is at equal distance from previous prime (2015543435429) and next prime (2015543435453).

It can be written as a sum of positive squares in only one way, i.e., 1634766816400 + 380776619041 = 1278580^2 + 617071^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2015543435441 is a prime.

It is not a weakly prime, because it can be changed into another prime (2015543435461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007771717720 + 1007771717721.

It is an arithmetic number, because the mean of its divisors is an integer number (1007771717721).

Almost surely, 22015543435441 is an apocalyptic number.

It is an amenable number.

2015543435441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2015543435441 is an equidigital number, since it uses as much as digits as its factorization.

2015543435441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576000, while the sum is 41.

The spelling of 2015543435441 in words is "two trillion, fifteen billion, five hundred forty-three million, four hundred thirty-five thousand, four hundred forty-one".