Base | Representation |
---|---|
bin | 10010110001011001… |
… | …010010011000110101 |
3 | 1221000201012012122021 |
4 | 102301121102120311 |
5 | 312234423042313 |
6 | 13132022233141 |
7 | 1312325504605 |
oct | 226131223065 |
9 | 57021165567 |
10 | 20156065333 |
11 | 8603634238 |
12 | 3aa62857b1 |
13 | 1b92b1b4a1 |
14 | d92d0cc05 |
15 | 7ce7e778d |
hex | 4b1652635 |
20156065333 has 2 divisors, whose sum is σ = 20156065334. Its totient is φ = 20156065332.
The previous prime is 20156065327. The next prime is 20156065339. The reversal of 20156065333 is 33356065102.
It is a balanced prime because it is at equal distance from previous prime (20156065327) and next prime (20156065339).
It can be written as a sum of positive squares in only one way, i.e., 18480227364 + 1675837969 = 135942^2 + 40937^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20156065333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20156065339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10078032666 + 10078032667.
It is an arithmetic number, because the mean of its divisors is an integer number (10078032667).
Almost surely, 220156065333 is an apocalyptic number.
It is an amenable number.
20156065333 is a deficient number, since it is larger than the sum of its proper divisors (1).
20156065333 is an equidigital number, since it uses as much as digits as its factorization.
20156065333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 34.
The spelling of 20156065333 in words is "twenty billion, one hundred fifty-six million, sixty-five thousand, three hundred thirty-three".
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