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20157152200151 = 171185714835303
BaseRepresentation
bin1001001010101001100111…
…11001011000010111010111
32122101000010121001102200012
410211110303321120113113
510120223321430401101
6110512022355110435
74150210010464421
oct445246371302727
978330117042605
1020157152200151
116471666a14aaa
1223167115a241b
13b32a71558595
144d987b867811
1524e5017e5bbb
hex125533e585d7

20157152200151 has 4 divisors (see below), whose sum is σ = 21342867035472. Its totient is φ = 18971437364832.

The previous prime is 20157152200139. The next prime is 20157152200153. The reversal of 20157152200151 is 15100225175102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20157152200151 - 222 = 20157148005847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20157152200153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 592857417635 + ... + 592857417668.

It is an arithmetic number, because the mean of its divisors is an integer number (5335716758868).

Almost surely, 220157152200151 is an apocalyptic number.

20157152200151 is a deficient number, since it is larger than the sum of its proper divisors (1185714835321).

20157152200151 is a wasteful number, since it uses less digits than its factorization.

20157152200151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1185714835320.

The product of its (nonzero) digits is 7000, while the sum is 32.

Adding to 20157152200151 its reverse (15100225175102), we get a palindrome (35257377375253).

The spelling of 20157152200151 in words is "twenty trillion, one hundred fifty-seven billion, one hundred fifty-two million, two hundred thousand, one hundred fifty-one".

Divisors: 1 17 1185714835303 20157152200151