Base | Representation |
---|---|
bin | 1001001011011010011000… |
… | …10111011111101101111110 |
3 | 2122110111201011000002012121 |
4 | 10211231030113133231332 |
5 | 10121140431113122200 |
6 | 110532032302553154 |
7 | 4152124540010500 |
oct | 445551427375576 |
9 | 78414634002177 |
10 | 20183332551550 |
11 | 6481781057553 |
12 | 231b7b92987ba |
13 | b35384496a7c |
14 | 4dac428a7d70 |
15 | 250034e21e1a |
hex | 125b4c5dfb7e |
20183332551550 has 36 divisors (see below), whose sum is σ = 43670141170920. Its totient is φ = 6919999731120.
The previous prime is 20183332551523. The next prime is 20183332551553. The reversal of 20183332551550 is 5515523338102.
It is a junction number, because it is equal to n+sod(n) for n = 20183332551497 and 20183332551506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20183332551553) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 4119045010 + ... + 4119049909.
It is an arithmetic number, because the mean of its divisors is an integer number (1213059476970).
Almost surely, 220183332551550 is an apocalyptic number.
20183332551550 is an abundant number, since it is smaller than the sum of its proper divisors (23486808619370).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20183332551550 is a wasteful number, since it uses less digits than its factorization.
20183332551550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8238094945 (or 8238094933 counting only the distinct ones).
The product of its (nonzero) digits is 540000, while the sum is 43.
Adding to 20183332551550 its reverse (5515523338102), we get a palindrome (25698855889652).
The spelling of 20183332551550 in words is "twenty trillion, one hundred eighty-three billion, three hundred thirty-two million, five hundred fifty-one thousand, five hundred fifty".
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