Base | Representation |
---|---|
bin | 1001001011011110000111… |
… | …10110000000000010010111 |
3 | 2122110200212211210111020122 |
4 | 10211233003312000002113 |
5 | 10121204032240140301 |
6 | 110533003230022155 |
7 | 4152225316603322 |
oct | 445570366000227 |
9 | 78420784714218 |
10 | 20185337036951 |
11 | 648260a588059 |
12 | 232007864795b |
13 | b356138518c8 |
14 | 4dad92bad7b9 |
15 | 250100dbd81b |
hex | 125bc3d80097 |
20185337036951 has 2 divisors, whose sum is σ = 20185337036952. Its totient is φ = 20185337036950.
The previous prime is 20185337036947. The next prime is 20185337037007. The reversal of 20185337036951 is 15963073358102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20185337036951 - 22 = 20185337036947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20185337036893 and 20185337036902.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20185337036911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10092668518475 + 10092668518476.
It is an arithmetic number, because the mean of its divisors is an integer number (10092668518476).
Almost surely, 220185337036951 is an apocalyptic number.
20185337036951 is a deficient number, since it is larger than the sum of its proper divisors (1).
20185337036951 is an equidigital number, since it uses as much as digits as its factorization.
20185337036951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4082400, while the sum is 53.
The spelling of 20185337036951 in words is "twenty trillion, one hundred eighty-five billion, three hundred thirty-seven million, thirty-six thousand, nine hundred fifty-one".
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