Base | Representation |
---|---|
bin | 10010110011110011… |
… | …001100101011110111 |
3 | 1221010112010001001212 |
4 | 102303303030223313 |
5 | 312330240142101 |
6 | 13140023112035 |
7 | 1313325446036 |
oct | 226363145367 |
9 | 57115101055 |
10 | 20196412151 |
11 | 8624391413 |
12 | 3ab78a261b |
13 | 1b9b2a6b46 |
14 | d9841271d |
15 | 7d31171bb |
hex | 4b3cccaf7 |
20196412151 has 2 divisors, whose sum is σ = 20196412152. Its totient is φ = 20196412150.
The previous prime is 20196412141. The next prime is 20196412153. The reversal of 20196412151 is 15121469102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20196412151 is a prime.
Together with 20196412153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20196412153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10098206075 + 10098206076.
It is an arithmetic number, because the mean of its divisors is an integer number (10098206076).
Almost surely, 220196412151 is an apocalyptic number.
20196412151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20196412151 is an equidigital number, since it uses as much as digits as its factorization.
20196412151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 32.
The spelling of 20196412151 in words is "twenty billion, one hundred ninety-six million, four hundred twelve thousand, one hundred fifty-one".
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