20204422541 has 2 divisors, whose sum is σ = 20204422542. Its totient is φ = 20204422540.

The previous prime is 20204422421. The next prime is 20204422543. The reversal of 20204422541 is 14522440202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14732861641 + 5471560900 = 121379^2 + 73970^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20204422541 is a prime.

It is a super-3 number, since 3×20204422541³ (a number of 32 digits) contains 333 as substring.

Together with 20204422543, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20204422541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20204422543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10102211270 + 10102211271.

It is an arithmetic number, because the mean of its divisors is an integer number (10102211271).

Almost surely, 2^20204422541 is an apocalyptic number.

It is an amenable number.

20204422541 is a deficient number, since it is larger than the sum of its proper divisors (1).

20204422541 is an equidigital number, since it uses as much as digits as its factorization.

20204422541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5120, while the sum is 26.

Adding to 20204422541 its reverse (14522440202), we get a palindrome (34726862743).

The spelling of 20204422541 in words is "twenty billion, two hundred four million, four hundred twenty-two thousand, five hundred forty-one".