Base | Representation |
---|---|
bin | 1001001100001100010010… |
… | …00010000000001010001011 |
3 | 2122120001212000120010022122 |
4 | 10212012021002000022023 |
5 | 10122110311223144321 |
6 | 110552222341441455 |
7 | 4154063421456413 |
oct | 446061102001213 |
9 | 78501760503278 |
10 | 20210120131211 |
11 | 6492077a3463a |
12 | 2324a3441028b |
13 | b37a63161c1a |
14 | 4dc264413643 |
15 | 250aa19e78ab |
hex | 12618908028b |
20210120131211 has 2 divisors, whose sum is σ = 20210120131212. Its totient is φ = 20210120131210.
The previous prime is 20210120131171. The next prime is 20210120131309. The reversal of 20210120131211 is 11213102101202.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20210120131211 - 214 = 20210120114827 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20210120131211.
It is not a weakly prime, because it can be changed into another prime (20210120136211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105060065605 + 10105060065606.
It is an arithmetic number, because the mean of its divisors is an integer number (10105060065606).
Almost surely, 220210120131211 is an apocalyptic number.
20210120131211 is a deficient number, since it is larger than the sum of its proper divisors (1).
20210120131211 is an equidigital number, since it uses as much as digits as its factorization.
20210120131211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 20210120131211 its reverse (11213102101202), we get a palindrome (31423222232413).
The spelling of 20210120131211 in words is "twenty trillion, two hundred ten billion, one hundred twenty million, one hundred thirty-one thousand, two hundred eleven".
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