Base | Representation |
---|---|
bin | 11101011010010011100… |
… | …011001011000001001111 |
3 | 21011012211122020001012101 |
4 | 131122103203023001033 |
5 | 231103213141200142 |
6 | 4144252443415531 |
7 | 266006664252163 |
oct | 35322343130117 |
9 | 7135748201171 |
10 | 2021110100047 |
11 | 70a169a63465 |
12 | 2878558245a7 |
13 | 118788c17c2c |
14 | 6db72382ca3 |
15 | 378914270b7 |
hex | 1d6938cb04f |
2021110100047 has 2 divisors, whose sum is σ = 2021110100048. Its totient is φ = 2021110100046.
The previous prime is 2021110100017. The next prime is 2021110100077. The reversal of 2021110100047 is 7400010111202.
It is a balanced prime because it is at equal distance from previous prime (2021110100017) and next prime (2021110100077).
It is a cyclic number.
It is not a de Polignac number, because 2021110100047 - 211 = 2021110097999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2021110099997 and 2021110100033.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2021110100017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010555050023 + 1010555050024.
It is an arithmetic number, because the mean of its divisors is an integer number (1010555050024).
Almost surely, 22021110100047 is an apocalyptic number.
2021110100047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021110100047 is an equidigital number, since it uses as much as digits as its factorization.
2021110100047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 2021110100047 its reverse (7400010111202), we get a palindrome (9421120211249).
The spelling of 2021110100047 in words is "two trillion, twenty-one billion, one hundred ten million, one hundred thousand, forty-seven".
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