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202112117 is a prime number
BaseRepresentation
bin11000000101111…
…11110001110101
3112002022100200222
430002333301311
5403220041432
632015544125
75002632104
oct1402776165
9462270628
10202112117
11a40a5909
125782b045
1332b4678c
141cbb203b
1512b25112
hexc0bfc75

202112117 has 2 divisors, whose sum is σ = 202112118. Its totient is φ = 202112116.

The previous prime is 202112089. The next prime is 202112149. The reversal of 202112117 is 711211202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 152423716 + 49688401 = 12346^2 + 7049^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-202112117 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 202112095 and 202112104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (202112917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101056058 + 101056059.

It is an arithmetic number, because the mean of its divisors is an integer number (101056059).

Almost surely, 2202112117 is an apocalyptic number.

It is an amenable number.

202112117 is a deficient number, since it is larger than the sum of its proper divisors (1).

202112117 is an equidigital number, since it uses as much as digits as its factorization.

202112117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 17.

The square root of 202112117 is about 14216.6141186993. The cubic root of 202112117 is about 586.8549656339.

Adding to 202112117 its reverse (711211202), we get a palindrome (913323319).

The spelling of 202112117 in words is "two hundred two million, one hundred twelve thousand, one hundred seventeen".