2021131127 has 2 divisors, whose sum is σ = 2021131128. Its totient is φ = 2021131126.

The previous prime is 2021131109. The next prime is 2021131129. The reversal of 2021131127 is 7211311202.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2021131127 is a prime.

Together with 2021131129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2021131099 and 2021131108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2021131129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010565563 + 1010565564.

It is an arithmetic number, because the mean of its divisors is an integer number (1010565564).

Almost surely, 2^2021131127 is an apocalyptic number.

2021131127 is a deficient number, since it is larger than the sum of its proper divisors (1).

2021131127 is an equidigital number, since it uses as much as digits as its factorization.

2021131127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 2021131127 is about 44956.9919701040. The cubic root of 2021131127 is about 1264.3427722226.

Adding to 2021131127 its reverse (7211311202), we get a palindrome (9232442329).

The spelling of 2021131127 in words is "two billion, twenty-one million, one hundred thirty-one thousand, one hundred twenty-seven".