Base | Representation |
---|---|
bin | 11101011010011000111… |
… | …010001010001101001111 |
3 | 21011020001220102001100211 |
4 | 131122120322022031033 |
5 | 231103404200341421 |
6 | 4144305414503251 |
7 | 266012135430400 |
oct | 35323072121517 |
9 | 7136056361324 |
10 | 2021200012111 |
11 | 70a205794755 |
12 | 28787b964b27 |
13 | 1187a1738b37 |
14 | 6db802a99a7 |
15 | 378992879e1 |
hex | 1d698e8a34f |
2021200012111 has 12 divisors (see below), whose sum is σ = 2408537995920. Its totient is φ = 1690202099040.
The previous prime is 2021200012081. The next prime is 2021200012129. The reversal of 2021200012111 is 1112100021202.
It is not a de Polignac number, because 2021200012111 - 25 = 2021200012079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2021200012091 and 2021200012100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2021200312111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 503034331 + ... + 503038348.
It is an arithmetic number, because the mean of its divisors is an integer number (200711499660).
Almost surely, 22021200012111 is an apocalyptic number.
2021200012111 is a deficient number, since it is larger than the sum of its proper divisors (387337983809).
2021200012111 is a wasteful number, since it uses less digits than its factorization.
2021200012111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1006072734 (or 1006072727 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2021200012111 its reverse (1112100021202), we get a palindrome (3133300033313).
Subtracting from 2021200012111 its reverse (1112100021202), we obtain a palindrome (909099990909).
The spelling of 2021200012111 in words is "two trillion, twenty-one billion, two hundred million, twelve thousand, one hundred eleven".
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