Base | Representation |
---|---|
bin | 1001001100010000001010… |
… | …00100010110101011000001 |
3 | 2122120021020001022102200222 |
4 | 10212020011010112223001 |
5 | 10122124041441404442 |
6 | 110553205040352425 |
7 | 4154166120553406 |
oct | 446100504265301 |
9 | 78507201272628 |
10 | 20212201122497 |
11 | 6492a4566a14a |
12 | 2325315315715 |
13 | b38005325907 |
14 | 4dc3c09522ad |
15 | 250b745578d2 |
hex | 126205116ac1 |
20212201122497 has 2 divisors, whose sum is σ = 20212201122498. Its totient is φ = 20212201122496.
The previous prime is 20212201122469. The next prime is 20212201122499. The reversal of 20212201122497 is 79422110221202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19905374863936 + 306826258561 = 4461544^2 + 553919^2 .
It is a cyclic number.
It is not a de Polignac number, because 20212201122497 - 228 = 20211932687041 is a prime.
Together with 20212201122499, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20212201122499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10106100561248 + 10106100561249.
It is an arithmetic number, because the mean of its divisors is an integer number (10106100561249).
Almost surely, 220212201122497 is an apocalyptic number.
It is an amenable number.
20212201122497 is a deficient number, since it is larger than the sum of its proper divisors (1).
20212201122497 is an equidigital number, since it uses as much as digits as its factorization.
20212201122497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
Adding to 20212201122497 its reverse (79422110221202), we get a palindrome (99634311343699).
The spelling of 20212201122497 in words is "twenty trillion, two hundred twelve billion, two hundred one million, one hundred twenty-two thousand, four hundred ninety-seven".
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