Base | Representation |
---|---|
bin | 11101011010100100111… |
… | …110010000010001010001 |
3 | 21011020121000021000222012 |
4 | 131122210332100101101 |
5 | 231104313004141423 |
6 | 4144341444552305 |
7 | 266020144002020 |
oct | 35324476202121 |
9 | 7136530230865 |
10 | 2021402412113 |
11 | 70a2a9a66887 |
12 | 2879176b2695 |
13 | 118804653656 |
14 | 6db9d1148b7 |
15 | 378abe18078 |
hex | 1d6a4f90451 |
2021402412113 has 12 divisors (see below), whose sum is σ = 2387099868480. Its totient is φ = 1676739322440.
The previous prime is 2021402412067. The next prime is 2021402412119. The reversal of 2021402412113 is 3112142041202.
It is not a de Polignac number, because 2021402412113 - 26 = 2021402412049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2021402412119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 150238733 + ... + 150252186.
It is an arithmetic number, because the mean of its divisors is an integer number (198924989040).
Almost surely, 22021402412113 is an apocalyptic number.
It is an amenable number.
2021402412113 is a deficient number, since it is larger than the sum of its proper divisors (365697456367).
2021402412113 is an equidigital number, since it uses as much as digits as its factorization.
2021402412113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 300490988 (or 300490957 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 2021402412113 its reverse (3112142041202), we get a palindrome (5133544453315).
The spelling of 2021402412113 in words is "two trillion, twenty-one billion, four hundred two million, four hundred twelve thousand, one hundred thirteen".
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