Base | Representation |
---|---|
bin | 11101011010100100111… |
… | …110010000010001010111 |
3 | 21011020121000021000222102 |
4 | 131122210332100101113 |
5 | 231104313004141434 |
6 | 4144341444552315 |
7 | 266020144002026 |
oct | 35324476202127 |
9 | 7136530230872 |
10 | 2021402412119 |
11 | 70a2a9a66892 |
12 | 2879176b269b |
13 | 11880465365c |
14 | 6db9d1148bd |
15 | 378abe1807e |
hex | 1d6a4f90457 |
2021402412119 has 2 divisors, whose sum is σ = 2021402412120. Its totient is φ = 2021402412118.
The previous prime is 2021402412067. The next prime is 2021402412151. The reversal of 2021402412119 is 9112142041202.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2021402412119 - 220 = 2021401363543 is a prime.
It is a super-2 number, since 2×20214024121192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2021402412091 and 2021402412100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2021402462119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010701206059 + 1010701206060.
It is an arithmetic number, because the mean of its divisors is an integer number (1010701206060).
Almost surely, 22021402412119 is an apocalyptic number.
2021402412119 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021402412119 is an equidigital number, since it uses as much as digits as its factorization.
2021402412119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 29.
The spelling of 2021402412119 in words is "two trillion, twenty-one billion, four hundred two million, four hundred twelve thousand, one hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •