Base | Representation |
---|---|
bin | 11101011011001000100… |
… | …101110111110111111111 |
3 | 21011022010122201200010211 |
4 | 131123020211313313333 |
5 | 231112024000004021 |
6 | 4144521033213251 |
7 | 266041021265161 |
oct | 35331045676777 |
9 | 7138118650124 |
10 | 2022000000511 |
11 | 70a586317897 |
12 | 287a63861227 |
13 | 11889b3b665a |
14 | 6dc18630931 |
15 | 378e460b3e1 |
hex | 1d6c8977dff |
2022000000511 has 2 divisors, whose sum is σ = 2022000000512. Its totient is φ = 2022000000510.
The previous prime is 2022000000479. The next prime is 2022000000533. The reversal of 2022000000511 is 1150000002202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2022000000511 - 25 = 2022000000479 is a prime.
It is a super-2 number, since 2×20220000005112 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2022000000491 and 2022000000500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2022000600511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011000000255 + 1011000000256.
It is an arithmetic number, because the mean of its divisors is an integer number (1011000000256).
Almost surely, 22022000000511 is an apocalyptic number.
2022000000511 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022000000511 is an equidigital number, since it uses as much as digits as its factorization.
2022000000511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 13.
Adding to 2022000000511 its reverse (1150000002202), we get a palindrome (3172000002713).
The spelling of 2022000000511 in words is "two trillion, twenty-two billion, five hundred eleven", and thus it is an aban number.
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