Base | Representation |
---|---|
bin | 11101011011001111001… |
… | …110000100001110010011 |
3 | 21011022102101222012100212 |
4 | 131123033032010032103 |
5 | 231112240431401042 |
6 | 4144540044434335 |
7 | 266043541414313 |
oct | 35331716041623 |
9 | 7138371865325 |
10 | 2022111200147 |
11 | 70a633068815 |
12 | 287a94b489ab |
13 | 1188b844ba5c |
14 | 6dc292d9443 |
15 | 378ee274482 |
hex | 1d6cf384393 |
2022111200147 has 2 divisors, whose sum is σ = 2022111200148. Its totient is φ = 2022111200146.
The previous prime is 2022111200119. The next prime is 2022111200159. The reversal of 2022111200147 is 7410021112202.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2022111200147 is a prime.
It is not a weakly prime, because it can be changed into another prime (2022111200177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011055600073 + 1011055600074.
It is an arithmetic number, because the mean of its divisors is an integer number (1011055600074).
Almost surely, 22022111200147 is an apocalyptic number.
2022111200147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022111200147 is an equidigital number, since it uses as much as digits as its factorization.
2022111200147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 2022111200147 its reverse (7410021112202), we get a palindrome (9432132312349).
The spelling of 2022111200147 in words is "two trillion, twenty-two billion, one hundred eleven million, two hundred thousand, one hundred forty-seven".
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