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202224113 = 7132222243
BaseRepresentation
bin11000000110110…
…11000111110001
3112002112001022222
430003123013301
5403232132423
632022210425
75003606450
oct1403330761
9462461288
10202224113
11a4171a73
1257883a15
1332b85750
141cc00b97
1512b483c8
hexc0db1f1

202224113 has 8 divisors (see below), whose sum is σ = 248891328. Its totient is φ = 160001424.

The previous prime is 202224107. The next prime is 202224131. The reversal of 202224113 is 311422202.

202224113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 202224113 - 210 = 202223089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 202224091 and 202224100.

It is not an unprimeable number, because it can be changed into a prime (202224133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1111031 + ... + 1111212.

It is an arithmetic number, because the mean of its divisors is an integer number (31111416).

Almost surely, 2202224113 is an apocalyptic number.

It is an amenable number.

202224113 is a deficient number, since it is larger than the sum of its proper divisors (46667215).

202224113 is a wasteful number, since it uses less digits than its factorization.

202224113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2222263.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 202224113 is about 14220.5524857510. The cubic root of 202224113 is about 586.9633432237.

Adding to 202224113 its reverse (311422202), we get a palindrome (513646315).

The spelling of 202224113 in words is "two hundred two million, two hundred twenty-four thousand, one hundred thirteen".

Divisors: 1 7 13 91 2222243 15555701 28889159 202224113