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2022400103131 is a prime number
BaseRepresentation
bin11101011011100000011…
…100001001001011011011
321011100011112120222202101
4131123200130021023123
5231113333411300011
64145024444544231
7266053650145132
oct35334034111333
97140145528671
102022400103131
1170a771152911
12287b55852077
13118933262875
146dc55820919
15379197e02c1
hex1d6e07092db

2022400103131 has 2 divisors, whose sum is σ = 2022400103132. Its totient is φ = 2022400103130.

The previous prime is 2022400103117. The next prime is 2022400103137. The reversal of 2022400103131 is 1313010042202.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2022400103131 - 215 = 2022400070363 is a prime.

It is a super-2 number, since 2×20224001031312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2022400103099 and 2022400103108.

It is not a weakly prime, because it can be changed into another prime (2022400103137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011200051565 + 1011200051566.

It is an arithmetic number, because the mean of its divisors is an integer number (1011200051566).

Almost surely, 22022400103131 is an apocalyptic number.

2022400103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2022400103131 is an equidigital number, since it uses as much as digits as its factorization.

2022400103131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 2022400103131 its reverse (1313010042202), we get a palindrome (3335410145333).

The spelling of 2022400103131 in words is "two trillion, twenty-two billion, four hundred million, one hundred three thousand, one hundred thirty-one".