Base | Representation |
---|---|
bin | 11101011011100000011… |
… | …100001001001011011011 |
3 | 21011100011112120222202101 |
4 | 131123200130021023123 |
5 | 231113333411300011 |
6 | 4145024444544231 |
7 | 266053650145132 |
oct | 35334034111333 |
9 | 7140145528671 |
10 | 2022400103131 |
11 | 70a771152911 |
12 | 287b55852077 |
13 | 118933262875 |
14 | 6dc55820919 |
15 | 379197e02c1 |
hex | 1d6e07092db |
2022400103131 has 2 divisors, whose sum is σ = 2022400103132. Its totient is φ = 2022400103130.
The previous prime is 2022400103117. The next prime is 2022400103137. The reversal of 2022400103131 is 1313010042202.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2022400103131 - 215 = 2022400070363 is a prime.
It is a super-2 number, since 2×20224001031312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2022400103099 and 2022400103108.
It is not a weakly prime, because it can be changed into another prime (2022400103137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011200051565 + 1011200051566.
It is an arithmetic number, because the mean of its divisors is an integer number (1011200051566).
Almost surely, 22022400103131 is an apocalyptic number.
2022400103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022400103131 is an equidigital number, since it uses as much as digits as its factorization.
2022400103131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 2022400103131 its reverse (1313010042202), we get a palindrome (3335410145333).
The spelling of 2022400103131 in words is "two trillion, twenty-two billion, four hundred million, one hundred three thousand, one hundred thirty-one".
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