Base | Representation |
---|---|
bin | 11101011011100011000… |
… | …000010010110010111101 |
3 | 21011100021112120012012111 |
4 | 131123203000102302331 |
5 | 231113430420243031 |
6 | 4145033023134021 |
7 | 266055011666023 |
oct | 35334300226275 |
9 | 7140245505174 |
10 | 2022443134141 |
11 | 70a793473731 |
12 | 287b68144311 |
13 | 11893c14abc1 |
14 | 6dc5b422713 |
15 | 3791d4901b1 |
hex | 1d6e3012cbd |
2022443134141 has 2 divisors, whose sum is σ = 2022443134142. Its totient is φ = 2022443134140.
The previous prime is 2022443134121. The next prime is 2022443134189. The reversal of 2022443134141 is 1414313442202.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1873670930041 + 148772204100 = 1368821^2 + 385710^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022443134141 - 223 = 2022434745533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2022443134121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011221567070 + 1011221567071.
It is an arithmetic number, because the mean of its divisors is an integer number (1011221567071).
Almost surely, 22022443134141 is an apocalyptic number.
It is an amenable number.
2022443134141 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022443134141 is an equidigital number, since it uses as much as digits as its factorization.
2022443134141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 2022443134141 its reverse (1414313442202), we get a palindrome (3436756576343).
The spelling of 2022443134141 in words is "two trillion, twenty-two billion, four hundred forty-three million, one hundred thirty-four thousand, one hundred forty-one".
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