Search a number
-
+
2023021025132 = 223891300142047
BaseRepresentation
bin11101011100000101011…
…100110001011101101100
321011101202210222002121112
4131130011130301131230
5231121121340301012
64145210225251152
7266105226663302
oct35340534613554
97141683862545
102023021025132
1170aa5a6a0798
122880a9793ab8
13118a01aa5433
146dcb4092272
1537954092122
hex1d70573176c

2023021025132 has 12 divisors (see below), whose sum is σ = 3549387791040. Its totient is φ = 1008910227696.

The previous prime is 2023021025117. The next prime is 2023021025147. The reversal of 2023021025132 is 2315201203202.

It is an interprime number because it is at equal distance from previous prime (2023021025117) and next prime (2023021025147).

It is a super-2 number, since 2×20230210251322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2023021025098 and 2023021025107.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650069468 + ... + 650072579.

It is an arithmetic number, because the mean of its divisors is an integer number (295782315920).

Almost surely, 22023021025132 is an apocalyptic number.

It is an amenable number.

2023021025132 is a deficient number, since it is larger than the sum of its proper divisors (1526366765908).

2023021025132 is a wasteful number, since it uses less digits than its factorization.

2023021025132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1300142440 (or 1300142438 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 2023021025132 its reverse (2315201203202), we get a palindrome (4338222228334).

The spelling of 2023021025132 in words is "two trillion, twenty-three billion, twenty-one million, twenty-five thousand, one hundred thirty-two".

Divisors: 1 2 4 389 778 1556 1300142047 2600284094 5200568188 505755256283 1011510512566 2023021025132