Base | Representation |
---|---|
bin | 11101011100001010010… |
… | …001101101111010110111 |
3 | 21011101222110100201020022 |
4 | 131130022101231322313 |
5 | 231121303103404421 |
6 | 4145222241155355 |
7 | 266110232242664 |
oct | 35341221557267 |
9 | 7141873321208 |
10 | 2023102013111 |
11 | 70aaa1387203 |
12 | 28811092bb5b |
13 | 118a157c040a |
14 | 6dcc0b34a6b |
15 | 3795b23d7ab |
hex | 1d70a46deb7 |
2023102013111 has 16 divisors (see below), whose sum is σ = 2086470640800. Its totient is φ = 1960726076928.
The previous prime is 2023102013087. The next prime is 2023102013171. The reversal of 2023102013111 is 1113102013202.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2023102013111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2023102013111.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2023102013171) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10051955 + ... + 10251243.
It is an arithmetic number, because the mean of its divisors is an integer number (130404415050).
Almost surely, 22023102013111 is an apocalyptic number.
2023102013111 is a deficient number, since it is larger than the sum of its proper divisors (63368627689).
2023102013111 is a wasteful number, since it uses less digits than its factorization.
2023102013111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201778.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2023102013111 its reverse (1113102013202), we get a palindrome (3136204026313).
Subtracting from 2023102013111 its reverse (1113102013202), we obtain a palindrome (909999999909).
The spelling of 2023102013111 in words is "two trillion, twenty-three billion, one hundred two million, thirteen thousand, one hundred eleven".
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