2023110013 has 4 divisors (see below), whose sum is σ = 2077788700. Its totient is φ = 1968431328.

The previous prime is 2023109999. The next prime is 2023110043. The reversal of 2023110013 is 3100113202.

2023110013 = T₅₉₈₂ + T₅₉₈₃ + ... + T₆₀₉₂.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3100113202 = 2 ⋅1550056601.

It can be written as a sum of positive squares in 2 ways, for example, as 1547084889 + 476025124 = 39333^2 + 21818^2 .

It is a cyclic number.

It is not a de Polignac number, because 2023110013 - 2⁵ = 2023109981 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2023109975 and 2023110002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2023110043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27339288 + ... + 27339361.

It is an arithmetic number, because the mean of its divisors is an integer number (519447175).

Almost surely, 2^2023110013 is an apocalyptic number.

It is an amenable number.

2023110013 is a deficient number, since it is larger than the sum of its proper divisors (54678687).

2023110013 is an equidigital number, since it uses as much as digits as its factorization.

2023110013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54678686.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 2023110013 is about 44978.9952422239. The cubic root of 2023110013 is about 1264.7552762337.

Adding to 2023110013 its reverse (3100113202), we get a palindrome (5123223215).

The spelling of 2023110013 in words is "two billion, twenty-three million, one hundred ten thousand, thirteen".