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202311441421 = 238796149627
BaseRepresentation
bin1011110001101010110…
…0111001110000001101
3201100012102200002000221
42330122230321300031
511303313212111141
6232535100151341
720421315610165
oct2743254716015
9640172602027
10202311441421
1178888597371
1233261838551
131610216bcab
149b1308b5a5
1553e1355bd1
hex2f1ab39c0d

202311441421 has 4 divisors (see below), whose sum is σ = 211107591072. Its totient is φ = 193515291772.

The previous prime is 202311441403. The next prime is 202311441443. The reversal of 202311441421 is 124144113202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202311441421 - 25 = 202311441389 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202311441401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4398074791 + ... + 4398074836.

It is an arithmetic number, because the mean of its divisors is an integer number (52776897768).

Almost surely, 2202311441421 is an apocalyptic number.

It is an amenable number.

202311441421 is a deficient number, since it is larger than the sum of its proper divisors (8796149651).

202311441421 is an equidigital number, since it uses as much as digits as its factorization.

202311441421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8796149650.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 202311441421 its reverse (124144113202), we get a palindrome (326455554623).

The spelling of 202311441421 in words is "two hundred two billion, three hundred eleven million, four hundred forty-one thousand, four hundred twenty-one".

Divisors: 1 23 8796149627 202311441421