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2023121117 is a prime number
BaseRepresentation
bin111100010010110…
…0110000011011101
312012222212012102202
41320211212003131
513120404333432
6532430301245
7101064150203
oct17045460335
95188765382
102023121117
11948aa9926
12485657825
132631b12b4
14152997073
15bc92d462
hex789660dd

2023121117 has 2 divisors, whose sum is σ = 2023121118. Its totient is φ = 2023121116.

The previous prime is 2023121081. The next prime is 2023121119. The reversal of 2023121117 is 7111213202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1277776516 + 745344601 = 35746^2 + 27301^2 .

It is a cyclic number.

It is not a de Polignac number, because 2023121117 - 28 = 2023120861 is a prime.

Together with 2023121119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2023121119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011560558 + 1011560559.

It is an arithmetic number, because the mean of its divisors is an integer number (1011560559).

Almost surely, 22023121117 is an apocalyptic number.

It is an amenable number.

2023121117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023121117 is an equidigital number, since it uses as much as digits as its factorization.

2023121117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 2023121117 is about 44979.1186774485. The cubic root of 2023121117 is about 1264.7575901327.

Adding to 2023121117 its reverse (7111213202), we get a palindrome (9134334319).

The spelling of 2023121117 in words is "two billion, twenty-three million, one hundred twenty-one thousand, one hundred seventeen".