Base | Representation |
---|---|
bin | 11101011100010011001… |
… | …100001011110000110111 |
3 | 21011102100212202100110211 |
4 | 131130103030023300313 |
5 | 231122104344314211 |
6 | 4145245142330251 |
7 | 266114026324156 |
oct | 35342314136067 |
9 | 7142325670424 |
10 | 2023251557431 |
11 | 710068838055 |
12 | 288152a29987 |
13 | 118a3a78ca90 |
14 | 6dcd694159d |
15 | 3796942ce21 |
hex | 1d71330bc37 |
2023251557431 has 8 divisors (see below), whose sum is σ = 2178898696800. Its totient is φ = 1867606190112.
The previous prime is 2023251557423. The next prime is 2023251557477. The reversal of 2023251557431 is 1347551523202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2023251557431 - 23 = 2023251557423 is a prime.
It is a super-3 number, since 3×20232515574313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2023251557491) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2816745 + ... + 3461293.
It is an arithmetic number, because the mean of its divisors is an integer number (272362337100).
Almost surely, 22023251557431 is an apocalyptic number.
2023251557431 is a deficient number, since it is larger than the sum of its proper divisors (155647139369).
2023251557431 is a wasteful number, since it uses less digits than its factorization.
2023251557431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 886025.
The product of its (nonzero) digits is 252000, while the sum is 40.
The spelling of 2023251557431 in words is "two trillion, twenty-three billion, two hundred fifty-one million, five hundred fifty-seven thousand, four hundred thirty-one".
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