Base | Representation |
---|---|
bin | 11101011100011100101… |
… | …001110010101101111111 |
3 | 21011102202221111000200212 |
4 | 131130130221302231333 |
5 | 231122421020022421 |
6 | 4145313013143035 |
7 | 266120664614504 |
oct | 35343451625577 |
9 | 7142687430625 |
10 | 2023410314111 |
11 | 71013a41031a |
12 | 28819802aa7b |
13 | 118a64636644 |
14 | 6dd0da694ab |
15 | 3797833be5b |
hex | 1d71ca72b7f |
2023410314111 has 4 divisors (see below), whose sum is σ = 2023565938152. Its totient is φ = 2023254690072.
The previous prime is 2023410314083. The next prime is 2023410314117. The reversal of 2023410314111 is 1114130143202.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2023410314111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2023410314117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77792516 + ... + 77818521.
It is an arithmetic number, because the mean of its divisors is an integer number (505891484538).
Almost surely, 22023410314111 is an apocalyptic number.
2023410314111 is a deficient number, since it is larger than the sum of its proper divisors (155624041).
2023410314111 is a wasteful number, since it uses less digits than its factorization.
2023410314111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155624040.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 2023410314111 its reverse (1114130143202), we get a palindrome (3137540457313).
The spelling of 2023410314111 in words is "two trillion, twenty-three billion, four hundred ten million, three hundred fourteen thousand, one hundred eleven".
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