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202344120113 is a prime number
BaseRepresentation
bin1011110001110010100…
…1100011111100110001
3201100021201011022202212
42330130221203330301
511303400043320423
6232542224421505
720422163433302
oct2743451437461
9640251138685
10202344120113
11788a4a87353
1233270777895
1316108b712b5
149b175567a9
1553e415d578
hex2f1ca63f31

202344120113 has 2 divisors, whose sum is σ = 202344120114. Its totient is φ = 202344120112.

The previous prime is 202344120107. The next prime is 202344120119. The reversal of 202344120113 is 311021443202.

It is a balanced prime because it is at equal distance from previous prime (202344120107) and next prime (202344120119).

It can be written as a sum of positive squares in only one way, i.e., 202258871824 + 85248289 = 449732^2 + 9233^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-202344120113 is a prime.

It is a super-2 number, since 2×2023441201132 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (202344120119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101172060056 + 101172060057.

It is an arithmetic number, because the mean of its divisors is an integer number (101172060057).

Almost surely, 2202344120113 is an apocalyptic number.

It is an amenable number.

202344120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

202344120113 is an equidigital number, since it uses as much as digits as its factorization.

202344120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 202344120113 its reverse (311021443202), we get a palindrome (513365563315).

The spelling of 202344120113 in words is "two hundred two billion, three hundred forty-four million, one hundred twenty thousand, one hundred thirteen".