Base | Representation |
---|---|
bin | 1001001101010111001000… |
… | …10010111011011110000111 |
3 | 2122200220120122100210221001 |
4 | 10212223210102323132013 |
5 | 10123240111314011100 |
6 | 111022510120234131 |
7 | 4160015313643114 |
oct | 446534422733607 |
9 | 78626518323831 |
10 | 20250306000775 |
11 | 64a81198a4194 |
12 | 233078a60b947 |
13 | b3b798891b76 |
14 | 50019756590b |
15 | 251b54996d6a |
hex | 126ae44bb787 |
20250306000775 has 12 divisors (see below), whose sum is σ = 25110872124984. Its totient is φ = 16199926940000.
The previous prime is 20250306000767. The next prime is 20250306000803. The reversal of 20250306000775 is 57700060305202.
It is not a de Polignac number, because 20250306000775 - 23 = 20250306000767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6642676 + ... + 9199225.
It is an arithmetic number, because the mean of its divisors is an integer number (2092572677082).
Almost surely, 220250306000775 is an apocalyptic number.
20250306000775 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
20250306000775 is a deficient number, since it is larger than the sum of its proper divisors (4860566124209).
20250306000775 is a wasteful number, since it uses less digits than its factorization.
20250306000775 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15893042 (or 15893037 counting only the distinct ones).
The product of its (nonzero) digits is 88200, while the sum is 37.
Adding to 20250306000775 its reverse (57700060305202), we get a palindrome (77950366305977).
The spelling of 20250306000775 in words is "twenty trillion, two hundred fifty billion, three hundred six million, seven hundred seventy-five", and thus it is an aban number.
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