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2025130503 = 31161367591
BaseRepresentation
bin111100010110101…
…0000101000000111
312020010122021210110
41320231100220013
513121413134003
6532541324103
7101120216364
oct17055205007
95203567713
102025130503
1194a151580
12486266633
13263735a96
14152d5b46b
15bcbc8a03
hex78b50a07

2025130503 has 8 divisors (see below), whose sum is σ = 2945644416. Its totient is φ = 1227351800.

The previous prime is 2025130487. The next prime is 2025130531. The reversal of 2025130503 is 3050315202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2025130503 - 24 = 2025130487 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2025130503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2025150503) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30683763 + ... + 30683828.

It is an arithmetic number, because the mean of its divisors is an integer number (368205552).

Almost surely, 22025130503 is an apocalyptic number.

2025130503 is a deficient number, since it is larger than the sum of its proper divisors (920513913).

2025130503 is a wasteful number, since it uses less digits than its factorization.

2025130503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61367605.

The product of its (nonzero) digits is 900, while the sum is 21.

The square root of 2025130503 is about 45001.4500099719. The cubic root of 2025130503 is about 1265.1761752683.

Adding to 2025130503 its reverse (3050315202), we get a palindrome (5075445705).

The spelling of 2025130503 in words is "two billion, twenty-five million, one hundred thirty thousand, five hundred three".

Divisors: 1 3 11 33 61367591 184102773 675043501 2025130503