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20254113451 = 1113141637157
BaseRepresentation
bin10010110111001111…
…010011111010101011
31221021112200120101001
4102313033103322223
5312440023112301
613145443535431
71314626060305
oct226717237253
957245616331
1020254113451
118653a12240
123b1308a577
131baa22a720
14da1d52975
157d8213c01
hex4b73d3eab

20254113451 has 8 divisors (see below), whose sum is σ = 23795042544. Its totient is φ = 16996458720.

The previous prime is 20254113437. The next prime is 20254113461. The reversal of 20254113451 is 15431145202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20254113451 - 29 = 20254112939 is a prime.

It is a super-2 number, since 2×202541134512 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (20254113461) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70818436 + ... + 70818721.

It is an arithmetic number, because the mean of its divisors is an integer number (2974380318).

Almost surely, 220254113451 is an apocalyptic number.

20254113451 is a deficient number, since it is larger than the sum of its proper divisors (3540929093).

20254113451 is a wasteful number, since it uses less digits than its factorization.

20254113451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 141637181.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 20254113451 its reverse (15431145202), we get a palindrome (35685258653).

The spelling of 20254113451 in words is "twenty billion, two hundred fifty-four million, one hundred thirteen thousand, four hundred fifty-one".

Divisors: 1 11 13 143 141637157 1558008727 1841283041 20254113451