Base | Representation |
---|---|
bin | 11101011110010101010… |
… | …001111110011001110010 |
3 | 21011121222222121200202100 |
4 | 131132111101332121302 |
5 | 231141042113114100 |
6 | 4150245510201230 |
7 | 266222100621633 |
oct | 35362521763162 |
9 | 7147888550670 |
10 | 2025434113650 |
11 | 710a88832922 |
12 | 288661953216 |
13 | 118cc79c466c |
14 | 7006275b88a |
15 | 37a45d51400 |
hex | 1d79547e672 |
2025434113650 has 36 divisors (see below), whose sum is σ = 5441666319882. Its totient is φ = 540115763520.
The previous prime is 2025434113559. The next prime is 2025434113673. The reversal of 2025434113650 is 563114345202.
2025434113650 is a `hidden beast` number, since 2 + 0 + 2 + 543 + 41 + 13 + 65 + 0 = 666.
It can be written as a sum of positive squares in 3 ways, for example, as 1922468213961 + 102965899689 = 1386531^2 + 320883^2 .
It is a super-2 number, since 2×20254341136502 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 2250481899 + ... + 2250482798.
Almost surely, 22025434113650 is an apocalyptic number.
2025434113650 is an abundant number, since it is smaller than the sum of its proper divisors (3416232206232).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2025434113650 is a wasteful number, since it uses less digits than its factorization.
2025434113650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4500964715 (or 4500964707 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 2025434113650 its reverse (563114345202), we get a palindrome (2588548458852).
The spelling of 2025434113650 in words is "two trillion, twenty-five billion, four hundred thirty-four million, one hundred thirteen thousand, six hundred fifty".
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