Base | Representation |
---|---|
bin | 1001001101011110111101… |
… | …11100111011000011111111 |
3 | 2122201022102201101211000021 |
4 | 10212233132330323003333 |
5 | 10123322214344010101 |
6 | 111024443302513011 |
7 | 4160224446341053 |
oct | 446573674730377 |
9 | 78638381354007 |
10 | 20254511313151 |
11 | 64a9987669665 |
12 | 2331562a35767 |
13 | b3bcb8baa89b |
14 | 500475c81c63 |
15 | 251cedc755a1 |
hex | 126bdef3b0ff |
20254511313151 has 2 divisors, whose sum is σ = 20254511313152. Its totient is φ = 20254511313150.
The previous prime is 20254511313121. The next prime is 20254511313181. The reversal of 20254511313151 is 15131311545202.
It is a balanced prime because it is at equal distance from previous prime (20254511313121) and next prime (20254511313181).
It is a cyclic number.
It is not a de Polignac number, because 20254511313151 - 213 = 20254511304959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20254511313121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10127255656575 + 10127255656576.
It is an arithmetic number, because the mean of its divisors is an integer number (10127255656576).
Almost surely, 220254511313151 is an apocalyptic number.
20254511313151 is a deficient number, since it is larger than the sum of its proper divisors (1).
20254511313151 is an equidigital number, since it uses as much as digits as its factorization.
20254511313151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 34.
Adding to 20254511313151 its reverse (15131311545202), we get a palindrome (35385822858353).
The spelling of 20254511313151 in words is "twenty trillion, two hundred fifty-four billion, five hundred eleven million, three hundred thirteen thousand, one hundred fifty-one".
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