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20303003111123 = 23941938086361
BaseRepresentation
bin1001001110111001010010…
…10010011100111011010011
32122212221121012021101101202
410213130221102130323103
510130121022244023443
6111103023150221415
74163562225665255
oct447345122347323
978787535241352
1020303003111123
116518500a5a157
12233aa367b486b
13b43746345c75
14502956175cd5
152531db0007b8
hex12772949ced3

20303003111123 has 8 divisors (see below), whose sum is σ = 21208256472096. Its totient is φ = 19399625924800.

The previous prime is 20303003111117. The next prime is 20303003111129. The reversal of 20303003111123 is 32111130030302.

It is an interprime number because it is at equal distance from previous prime (20303003111117) and next prime (20303003111129).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20303003111123 is a prime.

It is a super-2 number, since 2×203030031111232 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20303003111095 and 20303003111104.

It is not an unprimeable number, because it can be changed into a prime (20303003111129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 469021538 + ... + 469064823.

It is an arithmetic number, because the mean of its divisors is an integer number (2651032059012).

Almost surely, 220303003111123 is an apocalyptic number.

20303003111123 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

20303003111123 is a deficient number, since it is larger than the sum of its proper divisors (905253360973).

20303003111123 is an equidigital number, since it uses as much as digits as its factorization.

20303003111123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 938087325.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 20303003111123 its reverse (32111130030302), we get a palindrome (52414133141425).

The spelling of 20303003111123 in words is "twenty trillion, three hundred three billion, three million, one hundred eleven thousand, one hundred twenty-three".

Divisors: 1 23 941 21643 938086361 21575986303 882739265701 20303003111123