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203054400325 = 5271160310859
BaseRepresentation
bin1011110100011011111…
…1000100001101000101
3201102010012200022001101
42331012333010031011
511311323411302300
6233140520300101
720445606632140
oct2750677041505
9642105608041
10203054400325
1179129a08397
123342a611631
13161c006c94a
149b83a09057
1554366b1b6a
hex2f46fc4345

203054400325 has 12 divisors (see below), whose sum is σ = 287757093280. Its totient is φ = 139237302960.

The previous prime is 203054400323. The next prime is 203054400331. The reversal of 203054400325 is 523004450302.

It is not a de Polignac number, because 203054400325 - 21 = 203054400323 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 203054400293 and 203054400302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (203054400323) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 580155255 + ... + 580155604.

Almost surely, 2203054400325 is an apocalyptic number.

203054400325 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

It is an amenable number.

203054400325 is a deficient number, since it is larger than the sum of its proper divisors (84702692955).

203054400325 is a wasteful number, since it uses less digits than its factorization.

203054400325 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1160310876 (or 1160310871 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 28.

Adding to 203054400325 its reverse (523004450302), we get a palindrome (726058850627).

The spelling of 203054400325 in words is "two hundred three billion, fifty-four million, four hundred thousand, three hundred twenty-five".

Divisors: 1 5 7 25 35 175 1160310859 5801554295 8122176013 29007771475 40610880065 203054400325