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203115440551 = 365955511189
BaseRepresentation
bin1011110100101010011…
…1111010100110100111
3201102021110112110111111
42331022213322212213
511311440023044201
6233150540445451
720450250521032
oct2751247724647
9642243473444
10203115440551
1179160409861
1233446b49887
13161cc8c221a
149b8bb78019
15543bc1cb51
hex2f4a9fa9a7

203115440551 has 4 divisors (see below), whose sum is σ = 203170955400. Its totient is φ = 203059925704.

The previous prime is 203115440533. The next prime is 203115440557. The reversal of 203115440551 is 155044511302.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-203115440551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (203115440557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27751936 + ... + 27759253.

It is an arithmetic number, because the mean of its divisors is an integer number (50792738850).

Almost surely, 2203115440551 is an apocalyptic number.

203115440551 is a deficient number, since it is larger than the sum of its proper divisors (55514849).

203115440551 is an equidigital number, since it uses as much as digits as its factorization.

203115440551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55514848.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 203115440551 its reverse (155044511302), we get a palindrome (358159951853).

The spelling of 203115440551 in words is "two hundred three billion, one hundred fifteen million, four hundred forty thousand, five hundred fifty-one".

Divisors: 1 3659 55511189 203115440551