Base | Representation |
---|---|
bin | 11101100011111001101… |
… | …011100100101110111111 |
3 | 21012012102200220122212010 |
4 | 131203321223210232333 |
5 | 231240313324410101 |
6 | 4153115105342303 |
7 | 266523214650351 |
oct | 35437153445677 |
9 | 7165380818763 |
10 | 2031413513151 |
11 | 713576a73200 |
12 | 289850337993 |
13 | 11973b729889 |
14 | 7046c9270d1 |
15 | 37c95c6a2d6 |
hex | 1d8f9ae4bbf |
2031413513151 has 48 divisors (see below), whose sum is σ = 3061899187200. Its totient is φ = 1196213388480.
The previous prime is 2031413513147. The next prime is 2031413513159. The reversal of 2031413513151 is 1513153141302.
It is not a de Polignac number, because 2031413513151 - 22 = 2031413513147 is a prime.
It is a super-2 number, since 2×20314135131512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2031413513159) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9551710 + ... + 9762068.
It is an arithmetic number, because the mean of its divisors is an integer number (63789566400).
Almost surely, 22031413513151 is an apocalyptic number.
2031413513151 is a deficient number, since it is larger than the sum of its proper divisors (1030485674049).
2031413513151 is a wasteful number, since it uses less digits than its factorization.
2031413513151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 211140 (or 211129 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 30.
Adding to 2031413513151 its reverse (1513153141302), we get a palindrome (3544566654453).
The spelling of 2031413513151 in words is "two trillion, thirty-one billion, four hundred thirteen million, five hundred thirteen thousand, one hundred fifty-one".
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