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2031414310127 is a prime number
BaseRepresentation
bin11101100011111001101…
…110100111010011101111
321012012102202102011002202
4131203321232213103233
5231240314030411002
64153115134412115
7266523224510036
oct35437156472357
97165382364082
102031414310127
11713577467a64
1228985066103b
1311973b948567
147046ca9371d
1537c95d76502
hex1d8f9ba74ef

2031414310127 has 2 divisors, whose sum is σ = 2031414310128. Its totient is φ = 2031414310126.

The previous prime is 2031414310087. The next prime is 2031414310129. The reversal of 2031414310127 is 7210134141302.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2031414310127 - 224 = 2031397532911 is a prime.

It is a super-2 number, since 2×20314143101272 (a number of 25 digits) contains 22 as substring.

Together with 2031414310129, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2031414310127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2031414310129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1015707155063 + 1015707155064.

It is an arithmetic number, because the mean of its divisors is an integer number (1015707155064).

Almost surely, 22031414310127 is an apocalyptic number.

2031414310127 is a deficient number, since it is larger than the sum of its proper divisors (1).

2031414310127 is an equidigital number, since it uses as much as digits as its factorization.

2031414310127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 29.

Adding to 2031414310127 its reverse (7210134141302), we get a palindrome (9241548451429).

The spelling of 2031414310127 in words is "two trillion, thirty-one billion, four hundred fourteen million, three hundred ten thousand, one hundred twenty-seven".