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2032012113 = 36710109513
BaseRepresentation
bin111100100011110…
…0000101101010001
312020121120220120220
41321013200231101
513130143341423
6533345023253
7101232550365
oct17107405521
95217526526
102032012113
1195302185a
12488624b29
13264ca5141
14153c2d2a5
15bd5d79e3
hex791e0b51

2032012113 has 8 divisors (see below), whose sum is σ = 2749787808. Its totient is φ = 1334455584.

The previous prime is 2032012067. The next prime is 2032012127. The reversal of 2032012113 is 3112102302.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2032012113 - 214 = 2031995729 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2032012092 and 2032012101.

It is not an unprimeable number, because it can be changed into a prime (2032012313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5054556 + ... + 5054957.

It is an arithmetic number, because the mean of its divisors is an integer number (343723476).

Almost surely, 22032012113 is an apocalyptic number.

It is an amenable number.

2032012113 is a deficient number, since it is larger than the sum of its proper divisors (717775695).

2032012113 is a wasteful number, since it uses less digits than its factorization.

2032012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10109583.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 2032012113 is about 45077.8450350058. The cubic root of 2032012113 is about 1266.6076230635.

Adding to 2032012113 its reverse (3112102302), we get a palindrome (5144114415).

The spelling of 2032012113 in words is "two billion, thirty-two million, twelve thousand, one hundred thirteen".

Divisors: 1 3 67 201 10109513 30328539 677337371 2032012113